Grade 06 Mathematics - EC: M06.A-N.2.2.2
Grade 06 Mathematics - EC: M06.A-N.2.2.2
Continuum of Activities
The list below represents a continuum of activities: resources categorized by Standard/Eligible Content that teachers may use to move students toward proficiency. Using LEA curriculum and available materials and resources, teachers can customize the activity statements/questions for classroom use.
This continuum of activities offers:
- Instructional activities designed to be integrated into planned lessons
- Questions/activities that grow in complexity
- Opportunities for differentiation for each student’s level of performance
Grade Levels
6th Grade
Course, Subject
Mathematics
Activities
- Complete the following problem using the distributive property: 2(4 + 9) = (___ x 4) + (___ x 9)
- Complete the following problem using the distributive property: 8(3 + ___) = (8 x 3) + (___ x 7)
- Apply the distributive property to 16 + 24 as a multiple of a sum of two whole numbers with no common factor.
- The sum of 28 + 14 can be rewritten in three ways using the distributive property. They would be 7(4 + 2), 2(14 + 7) or 14(2 + 1). Rewrite the sum of 24 + 30 in at least two different ways.
- Write an equivalent statement to 5(4 + 8) using the distributive property. Tell what you did.
- Use the bank of numbers and symbols below to complete parts A and B:
A.) Write an expression of two whole numbers whose sum equals 24
B.) Use the Distributive Property to re-write the expression as a multiple of a sum of two whole numbers with no common factor.
- Determine which statement below is correctly showing an example of the distributive property and why. Explain why the other statement is incorrect, and fix it.
A) 55 + 40 = 5(11 +8)
B) 24 + 20 = 2(4 + 0)
Answer Key/Rubric
- 2(4 + 9) = (_2_ x 4) + (_2_ x 9)
- 8(3 + _7_) = (8 x 3) + (_8_ x 7)
- 8(2 + 3)
- Possible answers are
6(4 + 5) or 2(12 + 15) or 3(8 + 10)
- 20 + 40
Acceptable explanation may include, but is not limited to:
- Distributed the 5 to the sum inside the parentheses
- Multiplied 5 times 4 to get 20
- Multiplied 5 times 8 to get 40
- Acceptable answers may include, but are not limited to:
Part A
- 8 +16
- 3 + 21
- 9 + 15
Part B (keeping the order from above)
- 8(1 + 2)
- 3(1 + 7)
- 3(3 + 5)
- Statement A is correct.
Acceptable answers may include, but are not limited to
- A is correct because they found the common factor of 5 and divided 55 by 5 to get 11 and 40 by 5 to get 8
- Students solve both sides of the equation to see if they are equal
- Students might explain that when correctly applying the distributive property to express a sum of two whole numbers you have to find a common factor to multiply by.
- Statement B is incorrect
- A common factor of 2 was found correctly
- The factors listed in the parentheses are not correct, they are just the digits from the ones place of the original numbers
- Statement B should be 24 + 20 = 4(6 + 5)