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Balancing Chemical Reactions

Lesson Plan

Balancing Chemical Reactions

Objectives

In this lesson, students will learn that matter is not created nor destroyed during a chemical reaction. They will learn that chemical reactions occur in specific ratios, much like a recipe from a cook book. Students will:

  • balance chemical equations using coefficients in order to satisfy the law of conservation of matter.

  • determine whether chemical equations are balanced by creating “atom inventories.”

Essential Questions

Vocabulary

  • Law of Conservation of Matter: In a chemical reaction, matter is neither created nor destroyed.

  • Balanced” Chemical Equation: The number of atoms of each element is the same on the reactant and product sides.

  • Coefficient: A number that is placed in front of a chemical symbol or formula; used to balance a chemical equation by indicating the relative amounts of each substance.

  • Atom Inventory: A count of the number of atoms of each element on both the reactant and product side of a chemical equation.

  • Subscript: A number written below and to the right of a chemical symbol in a formula.

  • Superscript: A number written above and to the right of a chemical symbol in a formula.

Duration

45–60 minutes/1–2 class periods

Prerequisite Skills

Prerequisite Skills haven't been entered into the lesson plan.

Materials

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Related Materials & Resources

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Formative Assessment

  • View
    • Provide feedback on the completed practice worksheets and on student responses to the questions posed during the demonstration and instruction.

    • Provide feedback and corrections as students work through the example problems during the guided instruction portion of the lesson and the class discussion.

Suggested Instructional Supports

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    Scaffolding, Explicit Instruction
    W:

    The lesson focuses on the law of conservation of matter and how it relates to balancing a chemical equation. By the end of the lesson, students should be able to balance any type of chemical reaction, including those with polyatomic ions.

    H:

    The lesson hooks students by asking them to think about something they see every day, such as rust forming or filling up a gas tank. Additionally, students are asked to interpret a demonstration.

    E:

    Students will be forming hypotheses during the lesson. Additionally, students will interact with the teacher during the lesson’s example problems. The lesson concludes with students completing a practice worksheet.

    R:

    The demonstration will give students a jumping-off point that they can refer back to while the direct instruction is taking place. Furthermore, students will have an opportunity to revisit the key points as they work through the practice worksheet.

    E:

    Students will express their understanding of the lesson’s material during the lesson as they work on the example problems with the teacher. Students will also express their understanding as they complete the practice worksheet.

    T:

    Some students may benefit from helping with or even conducting a demonstration. In this case, ask students to write down a hypothesis based on previous knowledge before they perform the demonstration. There is a beyond-the-standards extension as well as an extension for those who may need a visual representation of the material.

    O:

    The lesson is organized so that students are asked to analyze two scenarios and a demonstration before they are taught any content. The lesson leads students to realize that atoms are rearranged before they are explicitly taught that. The lesson then walks students through how to balance a reaction and finishes with a practice worksheet.

Instructional Procedures

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    Have students take out their science notebooks. Tell them that you are going to show two pictures and perform one demonstration. They are to answer one simple question regarding all three things at the end. Show students the following pictures, or similar pictures, and ask the corresponding questions (S-C-3-1_Gas Tank and Rust Pictures.doc).

    l1-01gastank.PNG

    Pour 10 ml of vinegar into a resealable plastic bag. Add 1 spoonful of baking soda to the bag. Close the bag immediately. Tell students what the reactants are as you add them to the bag. Wait for the bag to expand. Ask students, “Where did the gas in the bag come from? Where did the baking soda go?”

    Allow students a few minutes to respond to the questions by writing in their notebooks. When students have completed their responses, ask for a few sample responses to each question. Then respond by saying, “The gasoline that you put in your car seems to disappear. The rust seems to appear from nowhere. The baking soda disappears, while a gas develops. These are all examples of chemical reactions. In the demonstration, the baking soda chemically reacts with the vinegar to produce carbon dioxide gas. That is why we saw the bag inflate. The atoms that make up the baking soda were not lost, nor were the atoms that make up the carbon dioxide gas created. In fact the atoms in baking soda (NaHCO3) are rearranged to produce carbon dioxide (CO2) and other products.” Explain that this is a closed system, in which the reactants and products are all within the sealed bag. If we measure the total mass of the reactants and the products, they will be the same. In an open system (i.e., open container), the CO2 gas would have dispersed in the surrounding environment.

    The reaction (two-step) is as follows:

    (1) CH3COOH + NaHCO3 H2CO3 + NaC2H3O2

    (2) H2CO3 CO2 + H2O

    Note: The last product of the first reaction is carbonic acid, which quickly decomposes into carbon dioxide and water. The CO2 is what you see foaming and bubbling in this reaction. Vinegar is an aqueous solution of acetic acid.

    Continue by saying, “As you can see, the atoms are not lost as the reaction proceeds nor are atoms created. They are merely rearranged. Let’s investigate why this is true and how chemists express this as they write chemical equations.”

    Let’s take a closer look at the reaction we just talked about. Look at the first reaction between vinegar and baking soda (sodium bicarbonate). Count the number of atoms of each element on the reactant side and then on the product side.” You may need to remind them that the reactants are on the left side of the arrow and that the products are on the right side. Guide them in forming lists like these:

    Reactant Side

    Product Side

    H = 5

    H = 5

    O = 5

    O = 5

    C = 3

    C = 3

    Na = 1

    Na = 1

    Tell them to do the same thing for the second reaction. Their atom inventory should look like this:

    Reactant Side

    Product Side

    H = 2

    H = 2

    O = 3

    O = 3

    C = 1

    C = 1

      At this point, say, “What do you notice about the number of atoms on the reactant and product sides of both reactions?” Students should recognize that the number of atoms of each element is the same. If students are not getting their atom inventory to match yours, remind them that the subscripts in the equation represent the number of atoms for the element before it only. For example, HCO3 has 1 hydrogen atom, 1 carbon atom and 3 oxygen atoms. Chemists do not write 1 as a coefficient.. Say, “The fact that atoms are neither created nor destroyed in a chemical reaction is called the law of conservation of matter. There are similar laws as well that you may be familiar with such as the law of conservation of energy and the law of conservation of mass.” If there are still questions, put an example on the board that has 1:1 molar ratios, such as:

      C + O2 CO2 or NaCl + K KCl + Na

      Optionally, give students colored jelly beans in a small cup with toothpicks. Designate a specific color for an element, such as red jelly beans for carbon and green jelly beans for oxygen. Have them construct models of the examples you did from the lesson. Remind them that they cannot add individual jellybeans, as that would be analogous to adding a subscript. They may only add complete sets (molecules/compounds) to satisfy the law of conservation of matter.

    After you have formatively assessed that students are ready to move on (through interaction with the class and examples on the board), give them a more difficult problem. Say, “I want you to complete the same task but for a slightly more challenging reaction. Create an atom inventory or a list of the number of each atom on both sides of the equation.” Use the following reaction:

    AlCl3 + Na Al + NaCl

    Reactant Side

    Product Side

    Al = 1

    Al = 1

    Cl = 3

    Cl = 1

    Na = 1

    Na = 1

    Ask students what they notice about the atom inventory. Was the law of conservation of matter satisfied? (No). Tell students, “According to the equation as it is currently written, 2 chlorine atoms seemed to have disappeared as the reaction progressed. Remember that matter cannot be destroyed, according to the law of conservation of matter. Chemists use something called coefficients to address this discrepancy. Coefficients are large numbers that are placed in front of a molecule, element, or compound to satisfy the conservation law. After coefficients are used and there are equal numbers of atoms of each element on both sides of the equation, it is said to be a balanced equation.”

    Say, “If we put a large 3 (a coefficient) in front of the NaCl, the equation would look like this” (write on the board):

    AlCl3 + Na Al + 3NaCl

    If you were to create an atom inventory (count of the number of atoms of each element for both the reactant and product side), you will see that it now looks like this” (write on the board):

    Reactant Side

    Product Side

    Al = 1

    Al = 1

    Cl = 3

    Cl = 1

    Na = 1

    Na = 3

    Notice that the coefficient of 3 is placed in front of the NaCl. The 3 is distributed to all atoms in the compound (both the Na and Cl), which fixes the chlorine discrepancy, but creates a new discrepancy for sodium. It would seem easier to put the coefficient in the middle of the NaCl like this: Na3Cl, but that is not allowed. The ionic compound NaCl must be written that way due to the ionic bond that sodium and chlorine make. The coefficients cannot be sandwiched between two atoms in a compound. The fact that chlorine was ‘fixed’ but now sodium is wrong is not a problem. Another coefficient will be placed like this” (write on the board):

    AlCl3 + 3Na Al + 3NaCl

    If you complete an atom inventory of the reaction, it should look like this” (write on the board):

    Reactant Side

    Product Side

    Al = 1

    Al = 1

    Cl = 3

    Cl = 3

    Na = 3

    Na = 3

    The law of conservation of matter has been satisfied and the equation is said to be balanced.” At this point, some students may ask what the coefficients mean and why chemists can just add them. It may help to compare a chemical equation to a recipe. Say, “Suppose you had the following recipe to make a s’more” (write on the board):

    1 s’more (S)

    2 graham crackers (G)

    1 marshmallow (M)

    1 piece of chocolate (C)

    If you were to write this recipe out as if it were a chemical reaction it may look something like this” (write on the board):

    2 G + 1M + 1C 1S

    Notice how you would need two crackers to make one s’more? If you had only one cracker and you were following the recipe, you would not be able to make a complete s’more. Balancing a chemical reaction is similar in that reactions need specific ratios of reactants in order to occur.” Do a few more examples on the board.

    Example 1

    Unbalanced: K + Zn(NO3)2 KNO3 + Zn

    Reactant Side

    Product Side

    K = 1

    K = 1

    Zn = 1

    Zn = 1

    N = 2

    N = 1

    O = 6

    O = 3

    The 2 coefficient is applied to both the potassium and the nitrate ion.

    l1-02balancedarrows.PNG

    Reactant Side

    Product Side

    K = 2

    K = 2

    Zn = 1

    Zn = 1

    N = 2

    N = 2

    O = 6

    O = 6

    Example 2

    Unbalanced: Mg(OH)2 + NaCl MgCl2 + NaOH

    Reactant Side

    Product Side

    Mg = 1

    Mg = 1

    O = 2

    O = 1

    H = 2

    H = 1

    Na = 1

    Na = 1

    Cl = 1

    Cl = 2

    Remind students that they cannot add subscripts. You may need to review how binary ionic compounds are formed. Some students may want to add a subscript of 2 to the sodium hydroxide on the product side. Remind them that sodium hydroxide forms as follows:

    Na+1 + OH-1 NaOH

    If you were to change that to Na(OH)2, you would be indicating that sodium forms a +2 ion, which it does not. Therefore, the balanced equation is written as:

    Balanced: Mg(OH)2 + 2NaCl MgCl2 + 2NaOH

    Example 3

    Unbalanced: CH4 + O2 CO2 + H2O

    Reactant Side

    Product Side

    C = 1

    C = 1

    H = 4

    H = 2

    O = 2

    O = 3

    Tell students, “Note that there is an odd number of oxygen atoms on the product side. Additionally, the oxygen atoms on the product side came from two different molecules. You need to add them together when making your atom inventory.” Write on the board:

    Balanced: CH4 + 2O2 CO2 + 2H2O

    At this time, you may do more example problems on the board and/or hand out the Balancing Practice Worksheet (S-C-3-1_Balancing Practice Worksheet and KEY.doc).

    Extension:

    • Students who might need additional practice with balancing equations can use interactive online activities such as those listed in Related Resources.

    • Students who may be going beyond the standards can balance more complex reactions such as the combustion of octane (a component of gasoline):

    Unbalanced: C8H18 + O2 CO2 + H2O

    (Note: Balanced: 2C8H18 + 25O2 16CO2 + 18H2O)

Related Instructional Videos

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DRAFT 11/19/2010
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